What is the inverse of f(x)= 4/(3+x^2) ?

The inverse of f(x)= 4/(3+x^2) is sqrt((4-3x)/x),-sqrt((4-3x)/x)

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inverse of f(x)= 4/(3+x^2)

inverse

f (x) = \frac{4}{3 + x ^{2}}

\frac{4 - 3 x}{x}, - \frac{4 - 3 x}{x}

Solution steps

y = \frac{4}{3 + x ^{2}}

Replace

x

with

y

x = \frac{4}{3 + y ^{2}}

Solve for

y, x = \frac{4}{3 + y ^{2}}

\frac{4 - 3 x}{x}, - \frac{4 - 3 x}{x}

f (x) = \frac{2 x - 1}{x ^{2} - 1}

f (x) = (x + 1) = 2 x

f (x) = 5^{x} - 3

f (x) = 9 + 3 x - 3

f (x) = \frac{4 x + 2}{8 x - 5}

What is the inverse of f(x)= 4/(3+x^2) ?
The inverse of f(x)= 4/(3+x^2) is sqrt((4-3x)/x),-sqrt((4-3x)/x)