What is the inverse of f(x)=-8x^2+7 ?

The inverse of f(x)=-8x^2+7 is sqrt(-(x-7)/8),-sqrt(-(x-7)/8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-8x^2+7

inverse

f (x) = - 8 x^{2} + 7

- \frac{x - 7}{8}, - - \frac{x - 7}{8}

Solution steps

y = - 8 x^{2} + 7

Replace

x

with

y

x = - 8 y^{2} + 7

Solve for

y, x = - 8 y^{2} + 7

- \frac{x - 7}{8}, - - \frac{x - 7}{8}

f (x) = 8 + 2 x - 2

27 cos^{2} (3 x)

f (x) = 6 - 2 x

f (x) = lo g_{7} (x^{4})

f (x) = 12 - 4 x

What is the inverse of f(x)=-8x^2+7 ?
The inverse of f(x)=-8x^2+7 is sqrt(-(x-7)/8),-sqrt(-(x-7)/8)