What is the inverse of f(x)= 3/4 x^3+2 ?

The inverse of f(x)= 3/4 x^3+2 is cube root of (4x-8)/3

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inverse of f(x)= 3/4 x^3+2

inverse

f (x) = \frac{3}{4} x^{3} + 2

3 \frac{4 x - 8}{3}

Solution steps

y = \frac{3}{4} x^{3} + 2

Replace

x

with

y

x = \frac{3}{4} y^{3} + 2

Solve for

y, x = \frac{3}{4} y^{3} + 2

3 \frac{4 x - 8}{3}

\frac{4 + x}{1 - x}

f (x) = e^{- 2 x}

g (x) = 12 - 2 x - \frac{3}{2}

f (x) = 5 + 2 sin (\frac{x - 1}{x + 1})

f (x) = 10 + 5 x - 5

What is the inverse of f(x)= 3/4 x^3+2 ?
The inverse of f(x)= 3/4 x^3+2 is cube root of (4x-8)/3