What is the inverse of log_{7}(x^4) ?

The inverse of log_{7}(x^4) is sqrt(7^{x/2)},-sqrt(7^{x/2)}

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inverse of log_{7}(x^4)

inverse

lo g_{7} (x^{4})

7^{\frac{x}{2}}, - 7^{\frac{x}{2}}

Solution steps

y = lo g_{7} (x^{4})

Replace

x

with

y

x = lo g_{7} (y^{4})

Solve for

y, x = lo g_{7} (y^{4})

7^{\frac{x}{2}}, - 7^{\frac{x}{2}}

f (x) = (1 - \frac{1}{0.15 x + 1})

f (x) = \frac{- 2}{x + 1}

X + 3

y = (x + 2)^{2} + 3

f (x) = \frac{( 9 x + 5 )}{( x - 2 )}

What is the inverse of log_{7}(x^4) ?
The inverse of log_{7}(x^4) is sqrt(7^{x/2)},-sqrt(7^{x/2)}