What is the inverse of f(x)=(1-1/(0.15x+1)) ?

The inverse of f(x)=(1-1/(0.15x+1)) is -(6.66666…x)/(x-1)

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inverse of f(x)=(1-1/(0.15x+1))

inverse

f (x) = (1 - \frac{1}{0.15 x + 1})

- \frac{6.66666 \dots x}{x - 1}

Solution steps

y = 1 - \frac{1}{0.15 x + 1}

Replace

x

with

y

x = 1 - \frac{1}{0.15 y + 1}

Solve for

y, x = 1 - \frac{1}{0.15 y + 1}

- \frac{6.66666 \dots x}{x - 1}

f (x) = \frac{- 2}{x + 1}

X + 3

y = (x + 2)^{2} + 3

f (x) = \frac{( 9 x + 5 )}{( x - 2 )}

y = \frac{x}{x - 3}

What is the inverse of f(x)=(1-1/(0.15x+1)) ?
The inverse of f(x)=(1-1/(0.15x+1)) is -(6.66666…x)/(x-1)