What is the domain of (4t-8)/(4-t^2) ?

The domain of (4t-8)/(4-t^2) is t 2

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domain of (4t-8)/(4-t^2)

domain

\frac{4 t - 8}{4 - t ^{2}}

t < - 2 or - 2 < t < 2 or t > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

t = 2, t = - 2

The function domain

t < - 2 or - 2 < t < 2 or t > 2

f (x) = - \frac{x ^{2}}{2} - 2 x

cos (\frac{θ}{3})

2 - x + 4

f (x) = \frac{1}{8} x - 5

4 x + y - 19 = 0, (6, 3)

What is the domain of (4t-8)/(4-t^2) ?
The domain of (4t-8)/(4-t^2) is t<-2\lor-2<t<2\lor t>2