What is the inverse of f(x)=(-8x+x^2+12)/(12) ?

The inverse of f(x)=(-8x+x^2+12)/(12) is 2(sqrt(3x+1)+2),2(-sqrt(3x+1)+2)

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inverse of f(x)=(-8x+x^2+12)/(12)

inverse

f (x) = \frac{- 8 x + x ^{2} + 12}{12}

2 (3 x + 1 + 2), 2 (- 3 x + 1 + 2)

Solution steps

y = \frac{- 8 x + x ^{2} + 12}{12}

Replace

x

with

y

x = \frac{- 8 y + y ^{2} + 12}{12}

Solve for

y, x = \frac{- 8 y + y ^{2} + 12}{12}

2 (3 x + 1 + 2), 2 (- 3 x + 1 + 2)

f (x) = f (x) = \frac{1}{2} (x - 4)^{2} + 1

4 x^{2} - 28 x + 16 y - 31 = 0

3 + x

- x^{2} - 1

f (x) = 7 + 5 x - 5

What is the inverse of f(x)=(-8x+x^2+12)/(12) ?
The inverse of f(x)=(-8x+x^2+12)/(12) is 2(sqrt(3x+1)+2),2(-sqrt(3x+1)+2)