What is the inverse of f(x)=1-(1/((0.15x+1))) ?

The inverse of f(x)=1-(1/((0.15x+1))) is -(6.66666…x)/(x-1)

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inverse of f(x)=1-(1/((0.15x+1)))

inverse

f (x) = 1 - (\frac{1}{( 0.15 x + 1 )})

- \frac{6.66666 \dots x}{x - 1}

Solution steps

y = 1 - \frac{1}{0.15 x + 1}

Replace

x

with

y

x = 1 - \frac{1}{0.15 y + 1}

Solve for

y, x = 1 - \frac{1}{0.15 y + 1}

- \frac{6.66666 \dots x}{x - 1}

f (x) = (x + 3) 2 - 2

f (x) = \frac{( x + 4 )}{( x + 7 )}

f (x) = 5 x - 2 - 2

\frac{5 x}{4 x - 5}

f (x) = - 5 (7) + 2

What is the inverse of f(x)=1-(1/((0.15x+1))) ?
The inverse of f(x)=1-(1/((0.15x+1))) is -(6.66666…x)/(x-1)