What is the inverse of y=2x^2+2x-1 ?

The inverse of y=2x^2+2x-1 is (-1+sqrt(2x+3))/2 ,-(sqrt(2x+3)+1)/2

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inverse of y=2x^2+2x-1

inverse

y = 2 x^{2} + 2 x - 1

\frac{- 1 + 2 x + 3}{2}, - \frac{2 x + 3 + 1}{2}

Solution steps

y = 2 x^{2} + 2 x - 1

Replace

x

with

y

x = 2 y^{2} + 2 y - 1

Solve for

y, x = 2 y^{2} + 2 y - 1

\frac{- 1 + 2 x + 3}{2}, - \frac{2 x + 3 + 1}{2}

f (x) = lo g_{3}^{2} (x - 1)

f (x) = \frac{9}{x + 6}

f (x) = \frac{8}{x + 5}

f (x) = \frac{8}{x + 9}

f (x) = 3 x^{2} + 5 x - 7

What is the inverse of y=2x^2+2x-1 ?
The inverse of y=2x^2+2x-1 is (-1+sqrt(2x+3))/2 ,-(sqrt(2x+3)+1)/2