What is the inverse of f(x)=log^2_{3}(x-1) ?

The inverse of f(x)=log^2_{3}(x-1) is 3^{sqrt(x)}+1,3^{-sqrt(x)}+1

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inverse of f(x)=log^2_{3}(x-1)

inverse

f (x) = lo g_{3}^{2} (x - 1)

3^{x} + 1, 3^{- x} + 1

Solution steps

y = lo g_{3} (x - 1)^{2}

Replace

x

with

y

x = lo g_{3} (y - 1)^{2}

Solve for

y, x = lo g_{3} (y - 1)^{2}

3^{x} + 1, 3^{- x} + 1

f (x) = \frac{9}{x + 6}

f (x) = \frac{8}{x + 5}

f (x) = \frac{8}{x + 9}

f (x) = 3 x^{2} + 5 x - 7

f (x) = 7 x^{2} + 4 x - 3

What is the inverse of f(x)=log^2_{3}(x-1) ?
The inverse of f(x)=log^2_{3}(x-1) is 3^{sqrt(x)}+1,3^{-sqrt(x)}+1