What is the inverse of f(x)=((5x-1))/(x+2) ?

The inverse of f(x)=((5x-1))/(x+2) is (-1-2x)/(x-5)

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inverse of f(x)=((5x-1))/(x+2)

inverse

f (x) = \frac{( 5 x - 1 )}{x + 2}

\frac{- 1 - 2 x}{x - 5}

Solution steps

y = \frac{5 x - 1}{x + 2}

Replace

x

with

y

x = \frac{5 y - 1}{y + 2}

Solve for

y, x = \frac{5 y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 5}

\frac{3}{x - 1} + 2

f (x) = lo g_{3} (x - 1)

lo g_{\frac{1}{2}} (x - 3)

- 6 + 3 (16 - 1)

- x^{2} + 6 x - 7

What is the inverse of f(x)=((5x-1))/(x+2) ?
The inverse of f(x)=((5x-1))/(x+2) is (-1-2x)/(x-5)