What is the inverse of (x^2-4)/(x-1) ?

The inverse of (x^2-4)/(x-1) is (x+sqrt(x^2-4(-4+x)))/2 ,(x-sqrt(x^2-4(-4+x)))/2

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inverse of (x^2-4)/(x-1)

inverse

\frac{x ^{2} - 4}{x - 1}

\frac{x + x ^{2} - 4 ( - 4 + x )}{2}, \frac{x - x ^{2} - 4 ( - 4 + x )}{2}

Solution steps

y = \frac{x ^{2} - 4}{x - 1}

Replace

x

with

y

x = \frac{y ^{2} - 4}{y - 1}

Solve for

y, x = \frac{y ^{2} - 4}{y - 1}

\frac{x + x ^{2} - 4 ( - 4 + x )}{2}, \frac{x - x ^{2} - 4 ( - 4 + x )}{2}

f (x) = \frac{1}{x ^{5}}

\frac{3}{2} x

\frac{z ( z - 4 )}{z ^{2} - 5 z + 6}

y = 2 x^{3} - 7

f (x) = \frac{9}{5} (x - 273) + 32

What is the inverse of (x^2-4)/(x-1) ?
The inverse of (x^2-4)/(x-1) is (x+sqrt(x^2-4(-4+x)))/2 ,(x-sqrt(x^2-4(-4+x)))/2