What is the inverse of f(x)=(4x+1)/(2x-1) ?

The inverse of f(x)=(4x+1)/(2x-1) is (1+x)/(2(-2+x))

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inverse of f(x)=(4x+1)/(2x-1)

inverse

f (x) = \frac{4 x + 1}{2 x - 1}

\frac{1 + x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x + 1}{2 x - 1}

Replace

x

with

y

x = \frac{4 y + 1}{2 y - 1}

Solve for

y, x = \frac{4 y + 1}{2 y - 1}

\frac{1 + x}{2 ( - 2 + x )}

y = lo g_{10} (x + 3)

4 π x^{2}

f (x) = \frac{( 2 x + 3 )}{( 5 - x )}

f (x) = 4 - (1 - \frac{x}{2})^{2}

\frac{3}{s ^{2} + 4 s + 3}

What is the inverse of f(x)=(4x+1)/(2x-1) ?
The inverse of f(x)=(4x+1)/(2x-1) is (1+x)/(2(-2+x))