What is the inverse of \sqrt[3]{sqrt(729x^5)} ?

The inverse of \sqrt[3]{sqrt(729x^5)} is (3^{4/5}x\sqrt[5]{x})/9

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inverse of \sqrt[3]{sqrt(729x^5)}

inverse

3 729 x^{5}

\frac{3 ^{\frac{4}{5}} x 5 x}{9}

Solution steps

y = 3 729 x^{5}

Replace

x

with

y

x = 3 729 y^{5}

Solve for

y, x = 3 729 y^{5}

\frac{3 ^{\frac{4}{5}} x 5 x}{9}

f (x) = \frac{1}{( \frac{1}{2} x - 2 )}

f (x) = (\frac{6}{5}) x - 9

\frac{2}{x ^{3} + 27}

f (x) = \frac{( 2 x - 3 )}{3 x - 1}

f (x) = \frac{x}{6} + 8

What is the inverse of \sqrt[3]{sqrt(729x^5)} ?
The inverse of \sqrt[3]{sqrt(729x^5)} is (3^{4/5}x\sqrt[5]{x})/9