What is the inverse of (3s+2)/(s^2+2s+10) ?

The inverse of (3s+2)/(s^2+2s+10) is (-2s+3+sqrt(-36s^2-4s+9))/(2s),(-2s+3-sqrt(-36s^2-4s+9))/(2s)

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inverse of (3s+2)/(s^2+2s+10)

inverse

\frac{3 s + 2}{s ^{2} + 2 s + 10}

\frac{- 2 s + 3 + - 36 s ^{2} - 4 s + 9}{2 s}, \frac{- 2 s + 3 - - 36 s ^{2} - 4 s + 9}{2 s}

Solution steps

y = \frac{3 s + 2}{s ^{2} + 2 s + 10}

Replace

s

with

y

s = \frac{3 y + 2}{y ^{2} + 2 y + 10}

Solve for

y, s = \frac{3 y + 2}{y ^{2} + 2 y + 10}

\frac{- 2 s + 3 + - 36 s ^{2} - 4 s + 9}{2 s}, \frac{- 2 s + 3 - - 36 s ^{2} - 4 s + 9}{2 s}

f (x) = \frac{( x + 3 )}{4 x - 2}

64 x^{2}

f (x) = - 2 x^{2} + 8 x - 7

y = (x + 1)^{2} + 2

4 - (\frac{1}{2})^{x + 2}

What is the inverse of (3s+2)/(s^2+2s+10) ?
The inverse of (3s+2)/(s^2+2s+10) is (-2s+3+sqrt(-36s^2-4s+9))/(2s),(-2s+3-sqrt(-36s^2-4s+9))/(2s)