What is the inverse of f(x)=\sqrt[3]{2/(x+1)} ?

The inverse of f(x)=\sqrt[3]{2/(x+1)} is 2/(x^3)-1

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inverse of f(x)=\sqrt[3]{2/(x+1)}

inverse

\frac{2}{x ^{3}} - 1

Solution steps

Replace

x

with

y

Solve for

\frac{2}{x ^{3}} - 1

2 lo g_{10} (x - 3) + 2

f (x) = ln (1 + x)

y = \frac{b ^{x} + b ^{- x}}{2}

10 - 2 p^{\frac{1}{2}}

f (x) = 4 + 3 x - 3

What is the inverse of f(x)=\sqrt[3]{2/(x+1)} ?
The inverse of f(x)=\sqrt[3]{2/(x+1)} is 2/(x^3)-1