What is the inverse of 1/2 log_{10}(6x) ?

The inverse of 1/2 log_{10}(6x) is (25^x*2^{2x-1})/3

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inverse of 1/2 log_{10}(6x)

inverse

\frac{1}{2} lo g_{10} (6 x)

\frac{2 5 ^{x} \cdot 2 ^{2 x - 1}}{3}

Solution steps

y = \frac{1}{2} lo g_{10} (6 x)

Replace

x

with

y

x = \frac{1}{2} lo g_{10} (6 y)

Solve for

y, x = \frac{1}{2} lo g_{10} (6 y)

\frac{2 5 ^{x} \cdot 2 ^{2 x - 1}}{3}

f (x) = 15 x + 5

f (x) = 15 x + 7

\frac{1}{x - 3}

f (x) = lo g_{2} (x - 2) - 1

f (12) = x + x

What is the inverse of 1/2 log_{10}(6x) ?
The inverse of 1/2 log_{10}(6x) is (25^x*2^{2x-1})/3