What is the inverse of log_{2}(x)-log_{2}(12) ?

The inverse of log_{2}(x)-log_{2}(12) is 3*2^{2+x}

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inverse of log_{2}(x)-log_{2}(12)

inverse

lo g_{2} (x) - lo g_{2} (12)

3 \cdot 2^{2 + x}

Solution steps

y = lo g_{2} (x) - lo g_{2} (12)

Replace

x

with

y

x = lo g_{2} (y) - lo g_{2} (12)

Solve for

y, x = lo g_{2} (y) - lo g_{2} (12)

3 \cdot 2^{2 + x}

f (x) = \frac{5 x + 3}{2}

f (x) = \frac{x ^{3}}{8} - 1

\frac{1}{3} x - 7

f (x) = 100 (1 - \frac{x}{400})^{2}

f (x) = - \frac{4}{x} + 3

What is the inverse of log_{2}(x)-log_{2}(12) ?
The inverse of log_{2}(x)-log_{2}(12) is 3*2^{2+x}