What is the inverse of f(x)=100(1-x/(400))^2 ?

The inverse of f(x)=100(1-x/(400))^2 is -40sqrt(x)+400,40sqrt(x)+400

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inverse of f(x)=100(1-x/(400))^2

inverse

f (x) = 100 (1 - \frac{x}{400})^{2}

- 40 x + 400, 40 x + 400

Solution steps

y = 100 (1 - \frac{x}{400})^{2}

Replace

x

with

y

x = 100 (1 - \frac{y}{400})^{2}

Solve for

y, x = 100 (1 - \frac{y}{400})^{2}

- 40 x + 400, 40 x + 400

f (x) = - \frac{4}{x} + 3

f (x) = \frac{π}{4}

f (x) = x^{2} + 4 x - 9

f (x) = \frac{1}{x ^{2} - 4}

f (x) = \frac{5 x}{x - 3}

What is the inverse of f(x)=100(1-x/(400))^2 ?
The inverse of f(x)=100(1-x/(400))^2 is -40sqrt(x)+400,40sqrt(x)+400