What is the inverse of f(x)=x^2+4x-9 ?

The inverse of f(x)=x^2+4x-9 is -2+sqrt(x+13),-sqrt(x+13)-2

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inverse of f(x)=x^2+4x-9

inverse

f (x) = x^{2} + 4 x - 9

- 2 + x + 13, - x + 13 - 2

Solution steps

y = x^{2} + 4 x - 9

Replace

x

with

y

x = y^{2} + 4 y - 9

Solve for

y, x = y^{2} + 4 y - 9

- 2 + x + 13, - x + 13 - 2

f (x) = \frac{1}{x ^{2} - 4}

f (x) = \frac{5 x}{x - 3}

y = 4 x - 9

f (x) = \frac{( 7 x + 3 )}{x - 5}

f (x) = 2 lo g_{9} (2 x - 5)

What is the inverse of f(x)=x^2+4x-9 ?
The inverse of f(x)=x^2+4x-9 is -2+sqrt(x+13),-sqrt(x+13)-2