What is the inverse of f(x)=2x^2+4x+6 ?

The inverse of f(x)=2x^2+4x+6 is (-4+sqrt(8x-32))/4 ,(-4-sqrt(8x-32))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2x^2+4x+6

inverse

f (x) = 2 x^{2} + 4 x + 6

\frac{- 4 + 8 x - 32}{4}, \frac{- 4 - 8 x - 32}{4}

Solution steps

y = 2 x^{2} + 4 x + 6

Replace

x

with

y

x = 2 y^{2} + 4 y + 6

Solve for

y, x = 2 y^{2} + 4 y + 6

\frac{- 4 + 8 x - 32}{4}, \frac{- 4 - 8 x - 32}{4}

g (x) = - 10

f (x) = \frac{1 - 3 x}{x - 4}

y = 1 - x

f (x) = (x - 19)^{2}

f (x) = f (x) = - x^{2} + 4

What is the inverse of f(x)=2x^2+4x+6 ?
The inverse of f(x)=2x^2+4x+6 is (-4+sqrt(8x-32))/4 ,(-4-sqrt(8x-32))/4