What is the inverse of f(x)=((x-1))/(2x+1) ?

The inverse of f(x)=((x-1))/(2x+1) is (-1-x)/(2x-1)

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inverse of f(x)=((x-1))/(2x+1)

inverse

f (x) = \frac{( x - 1 )}{2 x + 1}

\frac{- 1 - x}{2 x - 1}

Solution steps

y = \frac{x - 1}{2 x + 1}

Replace

x

with

y

x = \frac{y - 1}{2 y + 1}

Solve for

y, x = \frac{y - 1}{2 y + 1}

\frac{- 1 - x}{2 x - 1}

f (x) = - \frac{3}{4} x + 9

f (x) = 11 + 5 x - 5

f (x) = - 8 x + 12

f (x) = \frac{x}{3 x - 6}

What is the inverse of f(x)=((x-1))/(2x+1) ?
The inverse of f(x)=((x-1))/(2x+1) is (-1-x)/(2x-1)