What is the inverse of \sqrt[3]{x^2-8x+8} ?

The inverse of \sqrt[3]{x^2-8x+8} is 4+sqrt(x^3+8),4-sqrt(x^3+8)

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inverse of \sqrt[3]{x^2-8x+8}

inverse

4 + x^{3} + 8, 4 - x^{3} + 8

Solution steps

Replace

x

with

y

Solve for

4 + x^{3} + 8, 4 - x^{3} + 8

f (x) = - 8 x + 12

f (x) = \frac{x}{3 x - 6}

f (x) = 18500 (0.25 - x^{2})

f (x) = lo g_{7} (1 - sin (x))

f (x) = - 16 x^{2} + 100 x

What is the inverse of \sqrt[3]{x^2-8x+8} ?
The inverse of \sqrt[3]{x^2-8x+8} is 4+sqrt(x^3+8),4-sqrt(x^3+8)