What is the inverse of f(x)=-16x^2+100x ?

The inverse of f(x)=-16x^2+100x is -(-25+sqrt(-4x+625))/8 ,(sqrt(-4x+625)+25)/8

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inverse of f(x)=-16x^2+100x

inverse

f (x) = - 16 x^{2} + 100 x

- \frac{- 25 + - 4 x + 625}{8}, \frac{- 4 x + 625 + 25}{8}

Solution steps

y = - 16 x^{2} + 100 x

Replace

x

with

y

x = - 16 y^{2} + 100 y

Solve for

y, x = - 16 y^{2} + 100 y

- \frac{- 25 + - 4 x + 625}{8}, \frac{- 4 x + 625 + 25}{8}

g (x) = 2 x^{2} - 12 x + 13, x \leq 1

\frac{( s + 4 )}{( s + 1 ) ( s + 2 )}

\frac{( x - 1 )}{x + 1}

3 x - \frac{1}{4}

\frac{1}{4} x^{2}

What is the inverse of f(x)=-16x^2+100x ?
The inverse of f(x)=-16x^2+100x is -(-25+sqrt(-4x+625))/8 ,(sqrt(-4x+625)+25)/8