What is the inverse of g(x)=2x^2-12x+13,x<= 1 ?

The inverse of g(x)=2x^2-12x+13,x<= 1 is (12+sqrt(8x+40))/4 ,(12-sqrt(8x+40))/4

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inverse of g(x)=2x^2-12x+13,x<= 1

inverse

g (x) = 2 x^{2} - 12 x + 13, x \leq 1

\frac{12 + 8 x + 40}{4}, \frac{12 - 8 x + 40}{4}

Solution steps

y = 2 x^{2} - 12 x + 13

Replace

x

with

y

x = 2 y^{2} - 12 y + 13

Solve for

y, x = 2 y^{2} - 12 y + 13

\frac{12 + 8 x + 40}{4}, \frac{12 - 8 x + 40}{4}

\frac{( s + 4 )}{( s + 1 ) ( s + 2 )}

\frac{( x - 1 )}{x + 1}

3 x - \frac{1}{4}

\frac{1}{4} x^{2}

f (x) = 4 (π) r^{2}

What is the inverse of g(x)=2x^2-12x+13,x<= 1 ?
The inverse of g(x)=2x^2-12x+13,x<= 1 is (12+sqrt(8x+40))/4 ,(12-sqrt(8x+40))/4