What is the inverse of f(x)=4(pi)r^2 ?

The inverse of f(x)=4(pi)r^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4(pi)r^2

inverse

f (x) = 4 (π) r^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

Solution steps

x = 4 π r^{2}

Replace

r

with

x

r = 4 π x^{2}

Solve for

x, r = 4 π x^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

f (x) = \frac{x ^{2}}{4 - x ^{2}}

f (x) = 5 + 2 \cdot e^{x + 2}

f (x) = - ln (x - 3) + 2

f (x) = - 0.03 x^{2} + 45 x + 124.5

f (x) = (1 - x^{2})^{\frac{1}{2}}

What is the inverse of f(x)=4(pi)r^2 ?
The inverse of f(x)=4(pi)r^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)