What is the inverse of f(x)=(x^2)/(sqrt(4-x^2)) ?

The inverse of f(x)=(x^2)/(sqrt(4-x^2)) is

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inverse of f(x)=(x^2)/(sqrt(4-x^2))

inverse

f (x) = \frac{x ^{2}}{4 - x ^{2}}

\frac{- x ^{2} + x x ^{2} + 16}{2}, - \frac{- x ^{2} + x x ^{2} + 16}{2}, \frac{- x ^{2} - x x ^{2} + 16}{2}, - \frac{- x ^{2} - x x ^{2} + 16}{2}

Solution steps

y = \frac{x ^{2}}{4 - x ^{2}}

Replace

x

with

y

x = \frac{y ^{2}}{4 - y ^{2}}

Solve for

y, x = \frac{y ^{2}}{4 - y ^{2}}

\frac{- x ^{2} + x x ^{2} + 16}{2}, - \frac{- x ^{2} + x x ^{2} + 16}{2}, \frac{- x ^{2} - x x ^{2} + 16}{2}, - \frac{- x ^{2} - x x ^{2} + 16}{2}

f (x) = 5 + 2 \cdot e^{x + 2}

f (x) = - ln (x - 3) + 2

f (x) = - 0.03 x^{2} + 45 x + 124.5

f (x) = (1 - x^{2})^{\frac{1}{2}}

f (x) = 2 x^{\frac{5}{7}}

What is the inverse of f(x)=(x^2)/(sqrt(4-x^2)) ?
The inverse of f(x)=(x^2)/(sqrt(4-x^2)) is