What is the inverse of f(x)=((-4x-4))/(7x+8) ?

The inverse of f(x)=((-4x-4))/(7x+8) is (-4-8x)/(7x+4)

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inverse of f(x)=((-4x-4))/(7x+8)

inverse

f (x) = \frac{( - 4 x - 4 )}{7 x + 8}

\frac{- 4 - 8 x}{7 x + 4}

Solution steps

y = \frac{- 4 x - 4}{7 x + 8}

Replace

x

with

y

x = \frac{- 4 y - 4}{7 y + 8}

Solve for

y, x = \frac{- 4 y - 4}{7 y + 8}

\frac{- 4 - 8 x}{7 x + 4}

f (x) = arcsin (\frac{1}{2 x - 1})

f (x) = 8 x + 10

y = - 7 x - 5

\frac{2 s + 2}{s ^{2} + 2 s + 5}

f (x) = 3 + x^{2}

What is the inverse of f(x)=((-4x-4))/(7x+8) ?
The inverse of f(x)=((-4x-4))/(7x+8) is (-4-8x)/(7x+4)