What is the inverse of (2s+2)/(s^2+2s+5) ?

The inverse of (2s+2)/(s^2+2s+5) is (-s+1+sqrt(-4s^2+1))/s ,(-s+1-sqrt(-4s^2+1))/s

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inverse of (2s+2)/(s^2+2s+5)

inverse

\frac{2 s + 2}{s ^{2} + 2 s + 5}

\frac{- s + 1 + - 4 s ^{2} + 1}{s}, \frac{- s + 1 - - 4 s ^{2} + 1}{s}

Solution steps

y = \frac{2 s + 2}{s ^{2} + 2 s + 5}

Replace

s

with

y

s = \frac{2 y + 2}{y ^{2} + 2 y + 5}

Solve for

y, s = \frac{2 y + 2}{y ^{2} + 2 y + 5}

\frac{- s + 1 + - 4 s ^{2} + 1}{s}, \frac{- s + 1 - - 4 s ^{2} + 1}{s}

f (x) = 3 + x^{2}

+ 15 x^{3} - 14

f (x) = \frac{1}{3} (2^{3 x + 1}) - 1

f (x) = x^{2} + 4 x + 18

f (x) = (14 x - 13)^{2}

What is the inverse of (2s+2)/(s^2+2s+5) ?
The inverse of (2s+2)/(s^2+2s+5) is (-s+1+sqrt(-4s^2+1))/s ,(-s+1-sqrt(-4s^2+1))/s