What is the inverse of f(x)=(-4+4x)/(-3-3x) ?

The inverse of f(x)=(-4+4x)/(-3-3x) is -(-4+3x)/(4+3x)

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inverse of f(x)=(-4+4x)/(-3-3x)

inverse

f (x) = \frac{- 4 + 4 x}{- 3 - 3 x}

- \frac{- 4 + 3 x}{4 + 3 x}

Solution steps

y = \frac{- 4 + 4 x}{- 3 - 3 x}

Replace

x

with

y

x = \frac{- 4 + 4 y}{- 3 - 3 y}

Solve for

y, x = \frac{- 4 + 4 y}{- 3 - 3 y}

- \frac{- 4 + 3 x}{4 + 3 x}

f (x) = 3 x^{2} + 5 x - 3

y = x - \frac{x ^{2}}{x + 4}

- 10 x

f (x) = \frac{e ^{x}}{9 + 4 e ^{x}}

f (x) = \frac{2 x + 7}{3 x - 8}

What is the inverse of f(x)=(-4+4x)/(-3-3x) ?
The inverse of f(x)=(-4+4x)/(-3-3x) is -(-4+3x)/(4+3x)