What is the inverse of f(x)=(2x+7)/(3x-8) ?

The inverse of f(x)=(2x+7)/(3x-8) is (7+8x)/(3x-2)

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inverse of f(x)=(2x+7)/(3x-8)

inverse

f (x) = \frac{2 x + 7}{3 x - 8}

\frac{7 + 8 x}{3 x - 2}

Solution steps

y = \frac{2 x + 7}{3 x - 8}

Replace

x

with

y

x = \frac{2 y + 7}{3 y - 8}

Solve for

y, x = \frac{2 y + 7}{3 y - 8}

\frac{7 + 8 x}{3 x - 2}

f (x) = \frac{3}{2} x - 5

f (x) = (4 x - 1)^{2}

f (x) = \frac{4 x ^{2} - 1}{5 - 7 x ^{2}}

f (x) = \frac{1}{4 x + 1}

f (x) = e^{x^{2} + 3}

What is the inverse of f(x)=(2x+7)/(3x-8) ?
The inverse of f(x)=(2x+7)/(3x-8) is (7+8x)/(3x-2)