What is the inverse of f(x)=(4x-1)^2 ?

The inverse of f(x)=(4x-1)^2 is (sqrt(x)+1)/4 ,(-sqrt(x)+1)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(4x-1)^2

inverse

f (x) = (4 x - 1)^{2}

\frac{x + 1}{4}, \frac{- x + 1}{4}

Solution steps

y = (4 x - 1)^{2}

Replace

x

with

y

x = (4 y - 1)^{2}

Solve for

y, x = (4 y - 1)^{2}

\frac{x + 1}{4}, \frac{- x + 1}{4}

f (x) = \frac{4 x ^{2} - 1}{5 - 7 x ^{2}}

f (x) = \frac{1}{4 x + 1}

f (x) = e^{x^{2} + 3}

f (x) = 6 y = 2 x - 4

\frac{12}{3 S ^{2}}

What is the inverse of f(x)=(4x-1)^2 ?
The inverse of f(x)=(4x-1)^2 is (sqrt(x)+1)/4 ,(-sqrt(x)+1)/4