What is the inverse of f(x)=(4x^2-1)/(5-7x^2) ?

The inverse of f(x)=(4x^2-1)/(5-7x^2) is sqrt(-(-1-5x)/(4+7x)),-sqrt(-(-1-5x)/(4+7x))

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inverse of f(x)=(4x^2-1)/(5-7x^2)

inverse

f (x) = \frac{4 x ^{2} - 1}{5 - 7 x ^{2}}

- \frac{- 1 - 5 x}{4 + 7 x}, - - \frac{- 1 - 5 x}{4 + 7 x}

Solution steps

y = \frac{4 x ^{2} - 1}{5 - 7 x ^{2}}

Replace

x

with

y

x = \frac{4 y ^{2} - 1}{5 - 7 y ^{2}}

Solve for

y, x = \frac{4 y ^{2} - 1}{5 - 7 y ^{2}}

- \frac{- 1 - 5 x}{4 + 7 x}, - - \frac{- 1 - 5 x}{4 + 7 x}

f (x) = \frac{1}{4 x + 1}

f (x) = e^{x^{2} + 3}

f (x) = 6 y = 2 x - 4

\frac{12}{3 S ^{2}}

f (x) = \frac{7 x - \frac{1}{2}}{x + \frac{1}{3}}

What is the inverse of f(x)=(4x^2-1)/(5-7x^2) ?
The inverse of f(x)=(4x^2-1)/(5-7x^2) is sqrt(-(-1-5x)/(4+7x)),-sqrt(-(-1-5x)/(4+7x))