What is the inverse of f(x)=8(2x+10)^2+3,x>=-5 ?

The inverse of f(x)=8(2x+10)^2+3,x>=-5 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=8(2x+10)^2+3,x>=-5

inverse

f (x) = 8 (2 x + 10)^{2} + 3, x \geq - 5

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

Solution steps

y = 8 (2 x + 10)^{2} + 3

Replace

x

with

y

x = 8 (2 y + 10)^{2} + 3

Solve for

y, x = 8 (2 y + 10)^{2} + 3

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

f (x) = (- \frac{2}{3}) x^{2} + (\frac{1}{3})

f (x) = \frac{( 4 x ^{2} - 3 )}{5}

f (x) = 6 + 3 x - 3

f (x) = 5 + 2 e^{x + 2}

f (x) = 10 + 0.75 x

What is the inverse of f(x)=8(2x+10)^2+3,x>=-5 ?
The inverse of f(x)=8(2x+10)^2+3,x>=-5 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8