What is the inverse of f(x)=((4x^2-3))/5 ?

The inverse of f(x)=((4x^2-3))/5 is (sqrt(5x+3))/2 ,-(sqrt(5x+3))/2

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inverse of f(x)=((4x^2-3))/5

inverse

f (x) = \frac{( 4 x ^{2} - 3 )}{5}

\frac{5 x + 3}{2}, - \frac{5 x + 3}{2}

Solution steps

y = \frac{4 x ^{2} - 3}{5}

Replace

x

with

y

x = \frac{4 y ^{2} - 3}{5}

Solve for

y, x = \frac{4 y ^{2} - 3}{5}

\frac{5 x + 3}{2}, - \frac{5 x + 3}{2}

f (x) = 6 + 3 x - 3

f (x) = 5 + 2 e^{x + 2}

f (x) = 10 + 0.75 x

f (x) = 4 (π) x^{2}

ln (x) + 2

What is the inverse of f(x)=((4x^2-3))/5 ?
The inverse of f(x)=((4x^2-3))/5 is (sqrt(5x+3))/2 ,-(sqrt(5x+3))/2