What is the inverse of h(x)=(-2x-1)/(x+5) ?

The inverse of h(x)=(-2x-1)/(x+5) is (-1-5x)/(x+2)

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inverse of h(x)=(-2x-1)/(x+5)

inverse

h (x) = \frac{- 2 x - 1}{x + 5}

\frac{- 1 - 5 x}{x + 2}

Solution steps

y = \frac{- 2 x - 1}{x + 5}

Replace

x

with

y

x = \frac{- 2 y - 1}{y + 5}

Solve for

y, x = \frac{- 2 y - 1}{y + 5}

\frac{- 1 - 5 x}{x + 2}

f (x) = \frac{1}{5} (\frac{1}{5} x + 5) + 5

f (x) = \frac{5 x - 3}{x + 2}

y = 3 (x - 4)

f (x) = (x - 6)^{2} + 7

\frac{2 x + 3}{3 x - 1}

What is the inverse of h(x)=(-2x-1)/(x+5) ?
The inverse of h(x)=(-2x-1)/(x+5) is (-1-5x)/(x+2)