What is the inverse of f(x)=(x-6)^2+7 ?

The inverse of f(x)=(x-6)^2+7 is sqrt(x-7)+6,-sqrt(x-7)+6

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inverse of f(x)=(x-6)^2+7

inverse

f (x) = (x - 6)^{2} + 7

x - 7 + 6, - x - 7 + 6

Solution steps

y = (x - 6)^{2} + 7

Replace

x

with

y

x = (y - 6)^{2} + 7

Solve for

y, x = (y - 6)^{2} + 7

x - 7 + 6, - x - 7 + 6

\frac{2 x + 3}{3 x - 1}

f (x) = \frac{1}{4} (x^{2} - 4 x + 4)

f (x) = \frac{( 7 - 14 x ) 1}{2}

f (x) = \frac{- x ^{2}}{- 4 + x ^{2}}

f (x) = - 2 lo g_{4} (x)

What is the inverse of f(x)=(x-6)^2+7 ?
The inverse of f(x)=(x-6)^2+7 is sqrt(x-7)+6,-sqrt(x-7)+6