What is the inverse of f(x)=3(x+1)^2+2 ?

The inverse of f(x)=3(x+1)^2+2 is sqrt((x-2)/3)-1,-sqrt((x-2)/3)-1

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inverse of f(x)=3(x+1)^2+2

inverse

f (x) = 3 (x + 1)^{2} + 2

\frac{x - 2}{3} - 1, - \frac{x - 2}{3} - 1

Solution steps

y = 3 (x + 1)^{2} + 2

Replace

x

with

y

x = 3 (y + 1)^{2} + 2

Solve for

y, x = 3 (y + 1)^{2} + 2

\frac{x - 2}{3} - 1, - \frac{x - 2}{3} - 1

f (x) = \frac{20 + 0.4 x}{100 + x}

f (x) = \frac{3 3 x + 1}{5}

y = \frac{x + 1}{x - 1}

f (x) = \frac{8 x}{3 x - 4}

f (x) = \frac{1 - 2 x}{2 + x}

What is the inverse of f(x)=3(x+1)^2+2 ?
The inverse of f(x)=3(x+1)^2+2 is sqrt((x-2)/3)-1,-sqrt((x-2)/3)-1