What is the inverse of f(x)=(\sqrt[3]{x-5}+1)/4 ?

The inverse of f(x)=(\sqrt[3]{x-5}+1)/4 is 64x^3-48x^2+12x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(\sqrt[3]{x-5}+1)/4

inverse

f (x) = \frac{3 x - 5 + 1}{4}

64 x^{3} - 48 x^{2} + 12 x + 4

Solution steps

y = \frac{3 x - 5 + 1}{4}

Replace

x

with

y

x = \frac{3 y - 5 + 1}{4}

Solve for

y, x = \frac{3 y - 5 + 1}{4}

64 x^{3} - 48 x^{2} + 12 x + 4

2 \cdot 3 x

f (x) = \frac{- 4 x + 2}{4 x + 3}

f (x) = \frac{3 x - 4}{5 x + 8}

x^{2} - 2 x - 35

f (x) = 2 \cdot π \cdot r^{2} + 8 \cdot π \cdot r

What is the inverse of f(x)=(\sqrt[3]{x-5}+1)/4 ?
The inverse of f(x)=(\sqrt[3]{x-5}+1)/4 is 64x^3-48x^2+12x+4