What is the inverse of f(x)=log_{3}((x-1)^2) ?

The inverse of f(x)=log_{3}((x-1)^2) is sqrt(3^x)+1,-sqrt(3^x)+1

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inverse of f(x)=log_{3}((x-1)^2)

inverse

f (x) = lo g_{3} ((x - 1)^{2})

3^{x} + 1, - 3^{x} + 1

Solution steps

y = lo g_{3} ((x - 1)^{2})

Replace

x

with

y

x = lo g_{3} ((y - 1)^{2})

Solve for

y, x = lo g_{3} ((y - 1)^{2})

3^{x} + 1, - 3^{x} + 1

f (x) = \frac{8}{7 + x ^{2}}

f (x) = 9 - 2 x^{2}

f (x) = 2.6

f (x) = - 2 x + 4 + 1

What is the inverse of f(x)=log_{3}((x-1)^2) ?
The inverse of f(x)=log_{3}((x-1)^2) is sqrt(3^x)+1,-sqrt(3^x)+1