What is the inverse of f(x)=3(x+2)^2-19 ?

The inverse of f(x)=3(x+2)^2-19 is sqrt((x+19)/3)-2,-sqrt((x+19)/3)-2

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inverse of f(x)=3(x+2)^2-19

inverse

f (x) = 3 (x + 2)^{2} - 19

\frac{x + 19}{3} - 2, - \frac{x + 19}{3} - 2

Solution steps

y = 3 (x + 2)^{2} - 19

Replace

x

with

y

x = 3 (y + 2)^{2} - 19

Solve for

y, x = 3 (y + 2)^{2} - 19

\frac{x + 19}{3} - 2, - \frac{x + 19}{3} - 2

f (x) = 5 x - 200

f (x) = \frac{4}{3 + x}

f (x) = 4 cos (\frac{x}{3}), 3 π \leq x \leq 6 π

lo g_{3} (9 - x) + 2

\frac{x + 2}{7}

What is the inverse of f(x)=3(x+2)^2-19 ?
The inverse of f(x)=3(x+2)^2-19 is sqrt((x+19)/3)-2,-sqrt((x+19)/3)-2