What is the inverse of f(x)=1-e^{2(x-1)} ?

The inverse of f(x)=1-e^{2(x-1)} is (ln(1-x))/2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=1-e^{2(x-1)}

inverse

f (x) = 1 - e^{2 (x - 1)}

\frac{ln ( 1 - x )}{2} + 1

Solution steps

y = 1 - e^{2 (x - 1)}

Replace

x

with

y

x = 1 - e^{2 (y - 1)}

Solve for

y, x = 1 - e^{2 (y - 1)}

\frac{ln ( 1 - x )}{2} + 1

f (x) = 70 e^{- 0.0009 x}

\frac{5}{x - 1} + 3

f (x) = \frac{( 2 x + 3 )}{4 x + 4}

f (x) = \frac{( 15 - 2 x )}{3}

What is the inverse of f(x)=1-e^{2(x-1)} ?
The inverse of f(x)=1-e^{2(x-1)} is (ln(1-x))/2+1