What is the inverse of f(x)=3-2^{2-x} ?

The inverse of f(x)=3-2^{2-x} is -(ln(3-x)-2ln(2))/(ln(2))

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inverse of f(x)=3-2^{2-x}

inverse

f (x) = 3 - 2^{2 - x}

- \frac{ln ( 3 - x ) - 2 ln ( 2 )}{ln ( 2 )}

Solution steps

y = 3 - 2^{2 - x}

Replace

x

with

y

x = 3 - 2^{2 - y}

Solve for

y, x = 3 - 2^{2 - y}

- \frac{ln ( 3 - x ) - 2 ln ( 2 )}{ln ( 2 )}

f (x) = 1 + x^{2}

f (x) = \frac{5 x}{x - 4}

f (x) = \frac{2 - x ^{2}}{7}

f (x) = \frac{1}{x ^{2} - 9}

f (x) = 2 (x - 3)^{2} - 8

What is the inverse of f(x)=3-2^{2-x} ?
The inverse of f(x)=3-2^{2-x} is -(ln(3-x)-2ln(2))/(ln(2))