What is the inverse of f(x)=0.5(1-e^{2x}) ?

The inverse of f(x)=0.5(1-e^{2x}) is (ln(-2x+1))/2

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inverse of f(x)=0.5(1-e^{2x})

inverse

f (x) = 0.5 (1 - e^{2 x})

\frac{ln ( - 2 x + 1 )}{2}

Solution steps

y = 0.5 (1 - e^{2 x})

Replace

x

with

y

x = 0.5 (1 - e^{2 y})

Solve for

y, x = 0.5 (1 - e^{2 y})

\frac{ln ( - 2 x + 1 )}{2}

f (x) = lo g_{2} (x + 7)

y = 2 (3 x + 1) + 4

f (x) = ln (x^{59})

f (x) = \frac{2}{lo g _{3} ( x )}

\frac{x ^{2} + 1}{x}

What is the inverse of f(x)=0.5(1-e^{2x}) ?
The inverse of f(x)=0.5(1-e^{2x}) is (ln(-2x+1))/2