What is the inverse of f(x)=x^2+6x-3 ?

The inverse of f(x)=x^2+6x-3 is -3+sqrt(x+12),-sqrt(x+12)-3

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inverse of f(x)=x^2+6x-3

inverse

f (x) = x^{2} + 6 x - 3

- 3 + x + 12, - x + 12 - 3

Solution steps

y = x^{2} + 6 x - 3

Replace

x

with

y

x = y^{2} + 6 y - 3

Solve for

y, x = y^{2} + 6 y - 3

- 3 + x + 12, - x + 12 - 3

tan (\frac{40}{60})

f (x) = 1 - 2^{x}

f (x) = (1 - x^{2})^{\frac{1}{3}}

0.4 x + 6.6

f (x) = arctan (x^{2} - \frac{π}{4})

What is the inverse of f(x)=x^2+6x-3 ?
The inverse of f(x)=x^2+6x-3 is -3+sqrt(x+12),-sqrt(x+12)-3