What is the inverse of f(x)=sqrt(x^2+16) ?

The inverse of f(x)=sqrt(x^2+16) is sqrt(x^2-16),-sqrt(x^2-16)

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inverse of f(x)=sqrt(x^2+16)

inverse

f (x) = x^{2} + 16

x^{2} - 16, - x^{2} - 16

Solution steps

y = x^{2} + 16

Replace

x

with

y

x = y^{2} + 16

Solve for

y, x = y^{2} + 16

x^{2} - 16, - x^{2} - 16

f (x) = 9 - 2 x^{2}

f (x) = \frac{( 5 x - 3 )}{2 x + 3}

f (x) = - 4 x^{2} + 2

\frac{1}{x + 3} + 2

arctan (- 3)

What is the inverse of f(x)=sqrt(x^2+16) ?
The inverse of f(x)=sqrt(x^2+16) is sqrt(x^2-16),-sqrt(x^2-16)