What is the inverse of-1/z 1/((z-0.8)) ?

The inverse of-1/z 1/((z-0.8)) is (0.8z+sqrt(0.64z^2-4z))/(2z),(0.8z-sqrt(0.64z^2-4z))/(2z)

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inverse of-1/z 1/((z-0.8))

inverse

- \frac{1}{z} \frac{1}{( z - 0.8 )}

\frac{0.8 z + 0.64 z ^{2} - 4 z}{2 z}, \frac{0.8 z - 0.64 z ^{2} - 4 z}{2 z}

Solution steps

y = - \frac{1}{z} \cdot \frac{1}{z - 0.8}

Replace

z

with

y

z = - \frac{1}{y} \cdot \frac{1}{y - 0.8}

Solve for

y, z = - \frac{1}{y} \frac{1}{y - 0.8}

\frac{0.8 z + 0.64 z ^{2} - 4 z}{2 z}, \frac{0.8 z - 0.64 z ^{2} - 4 z}{2 z}

f (x) = \frac{( x ^{2} + 1 )}{( x ^{2} + 2 )}

y = \frac{2}{- x + 4}

+ 2 tan (x - \frac{π}{4})

(8 - 2 x)^{2}

2 + x - 6

What is the inverse of-1/z 1/((z-0.8)) ?
The inverse of-1/z 1/((z-0.8)) is (0.8z+sqrt(0.64z^2-4z))/(2z),(0.8z-sqrt(0.64z^2-4z))/(2z)