What is the inverse of f(x)=2pix^2+16x ?

The inverse of f(x)=2pix^2+16x is (-16+sqrt(256+8pix))/(4pi),(-16-sqrt(256+8pix))/(4pi)

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inverse of f(x)=2pix^2+16x

inverse

f (x) = 2 π x^{2} + 16 x

\frac{- 16 + 256 + 8 π x}{4 π}, \frac{- 16 - 256 + 8 π x}{4 π}

Solution steps

y = 2 π x^{2} + 16 x

Replace

x

with

y

x = 2 π y^{2} + 16 y

Solve for

y, x = 2 π y^{2} + 16 y

\frac{- 16 + 256 + 8 π x}{4 π}, \frac{- 16 - 256 + 8 π x}{4 π}

f (x) = \frac{5 - x}{9}

y = 2^{3 x}

f (x) = (\frac{( 2 x + 3 )}{( 3 x - 2 )})

f (x) = 10 3 - 2 x - 5 + 8

f (x) = arcsin (y)

What is the inverse of f(x)=2pix^2+16x ?
The inverse of f(x)=2pix^2+16x is (-16+sqrt(256+8pix))/(4pi),(-16-sqrt(256+8pix))/(4pi)