What is the inverse of f(x)=(x-4)^2,[4,infinity ] ?

The inverse of f(x)=(x-4)^2,[4,infinity ] is sqrt(x)+4,-sqrt(x)+4

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inverse of f(x)=(x-4)^2,[4,infinity ]

inverse

f (x) = (x - 4)^{2}, [4, \infty]

x + 4, - x + 4

Solution steps

y = (x - 4)^{2}

Replace

x

with

y

x = (y - 4)^{2}

Solve for

y, x = (y - 4)^{2}

x + 4, - x + 4

16 x^{2}

3 x^{2} + 6

f (x) = \frac{5 - x}{2}

f (x) = \frac{( - y ^{2} + 10 y + 35 )}{60}

f (x) = \frac{( - x - 2 )}{x + 4}

What is the inverse of f(x)=(x-4)^2,[4,infinity ] ?
The inverse of f(x)=(x-4)^2,[4,infinity ] is sqrt(x)+4,-sqrt(x)+4