What is the inverse of (4x^2+7)/4 ?

The inverse of (4x^2+7)/4 is (sqrt(4x-7))/2 ,-(sqrt(4x-7))/2

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inverse of (4x^2+7)/4

inverse

\frac{4 x ^{2} + 7}{4}

\frac{4 x - 7}{2}, - \frac{4 x - 7}{2}

Solution steps

y = \frac{4 x ^{2} + 7}{4}

Replace

x

with

y

x = \frac{4 y ^{2} + 7}{4}

Solve for

y, x = \frac{4 y ^{2} + 7}{4}

\frac{4 x - 7}{2}, - \frac{4 x - 7}{2}

f (x) = 5 5 x + 4

x - 1 - 3

f (x) = 4 - \frac{3}{x - 2}

f (x) = x^{2} - 16, [0, \infty]

f (x) = 100 x^{2} + 7, x \geq 0

What is the inverse of (4x^2+7)/4 ?
The inverse of (4x^2+7)/4 is (sqrt(4x-7))/2 ,-(sqrt(4x-7))/2